AFFORDABLE-ESSAY-WRITERS

Faculty of Computing, Engineering and Science Assessment Cover Sheet and Feedback Form 2019-20 Module Code: NG3S229 Module Title: Mechanics and Control Module Team: Fan Zhang Joao Ramos Assessment Title and Tasks: Report 1 Assessment No. 1 Date Set: 04-Nov-19 Submission Date: 06-Dec-19 Return Date: 13-Jan-20 IT IS YOUR RESPONSIBILITY TO KEEP RECORDS OF ALL WORK SUBMITTED Marking and Assessment This assignment will be marked out of 100% This assignment contributes to 15% of the total module marks. Learning Outcomes to be assessed (as specified in the validated module descriptor https://icis.southwales.ac.uk/ ): 1) Demonstrate an understanding of complex static and dynamics systems and solve problems using experimental analysis 2) Demonstrate an understanding and apply the concepts of static and dynamic analysis to solve complex engineering problems Provisional mark only: subject to change and / or confirmation by the Assessment Board   Assessment Task: GEARS Your task is to solve the following questions. This is not a Report but an extended Tutorial, please submit all your workings in a clear and concise manner – clearly outlining the result for each question. Required Information: Lewis Formula The Lewis formula is a simple approach to calculating the bending stress in gears, given by: σ=W_t/(K_v FmY) (N/m^2) Equation 1 Where: σ – bending stress in a gear (N/m2) W_t – transmitted load (N) (found by using Equation 2) K_v – velocity factor (found by using Equation 5) F – face width (m) m – module (m/tooth) Y – Lewis form factor Y (found in Table 1) The Load transmitted by the Gear W_t: W_t=Power/V (N) Equation 2 Where: W_t – transmitted load (N) Power – Power transmitted (W) V – pitch line velocity (m/s) The pitch line velocity V: V=d_p/2×ω (m/s) Equation 3 Where: V – pitch line velocity (m/s) d_p – pinion pitch diameter (m) ω – angular velocity (rad/s) The pinion pitch diameter d_p: d_p=m×N (m or mm) Equation 4 Where: m – module (m/tooth or mm/tooth) N – number of teeth The velocity factor K_v, given by the Barth equation: K_v=6.1/(6.1+V) (N/m^2) Equation 5 Where: K_v – velocity factor V – pitch line velocity (m/s)   Table 1 – Values for the Lewis form factor Y defined for two different tooth standards (Mitchener and Mabie 1982) N, number of teeth Y (φ = 20°; a = m; b = 1.25 m) 12 0.22960 13 0.24317 14 0.25530 15 0.26622 16 0.27610 17 0.28508 18 0.29327 19 0.30078 20 0.30769 21 0.31406 22 0.31997 24 0.33056 26 0.33979 28 0.34790 30 0.35510 34 0.36731 38 0.37727 45 0.39093 50 0.39860 60 0.41047 75 0.42283 100 0.43574 150 0.44930 300 0.46364 Rack 0.47897 a – addendum b – dedendum φ – pressure angle m – module Table 2 – Permissible bending stresses for various commonly used gear materials Material Treatment σUTS (MPa) Permissible bending stress σp (MPa) Nylon 65 (20°C) 27 Tufnol 110 31 080M40 540 131 080M40 Induction hardened 540 117 817M40 772 221 817M40 Induction hardened 772 183 045M10 494 117 045M10 Case hardened 494 276 655M13 Case hardened 849 345 Example 1: A 20° full depth spur pinion is to transmit 1.25 kW at 850 rpm. The pinion has 18 teeth. Determine the Lewis bending stress if the module is 2 and the face width is 25 mm: Step by step solution: Calculate the pinion pitch diameter from Equation 4: d_p=m×N=2 mm/tooth×18 teeth=36 mm=0.036 m Calculate the pitch line velocity from Equation 3: V=d_p/2×ω =0.036/2×850×2π/60=1.602 m/s Calculate the velocity factor from Equation 5: K_v=6.1/(6.1+V)=6.1/(6.1+1.602)=0.792 (N/m^2) Calculate the transmitted load from Equation 2: W_t=Power/V=1250/1.602=780.2 (N) Calculate the bending stress load from Equation 1, taking the Lewis form factor Y from Table 1 for 18 teeth Y=0.29327: σ=W_t/(K_v FmY)=780.2/(0.792×0.025×0.002×0.29327)=67.18 (MN/m^2) Example 2: A gearbox is required to transmit 18 kW from a shaft rotating at 2650 rpm. The desired output speed is approximately 12 000 rpm. For space limitation and standardisation reasons a double step-up gearbox is requested with equal ratios. Using the limited selection of gears presented in Tables 2 to 5, select suitable gears for the gear wheels and pinions. Step by step solution: The steps are the following: Sketch the solution Find the gear ratio Select a material Select a gear from the table by rearranging the Lewis equation (Equation 1) to find the gear face width F and. Finding the gear ratio: G=(12 000 rpm)/(2650 rpm)=4.528 Total gear ratio of 1 to 4.528. A double gearbox is requested with equal ratios. Therefore the ratio for each gear pair should be: √G=√4.528=2.128 Note that the minimum number of teeth permissible when using a pressure angle of 20° is 18. This means the small gear needs to have 18 teeth. So the large gear should have approximately: 18×G=18×2.128=38.3 The nearest integer is 38. This gives us a real gear ratio of 38/18=2.11 for each gear pair. Selecting a material: The next step is to select a material. The stronger steel in Table 2 is the 655M13 which will be selected prior to a more detailed consideration. For 655M13, the permissible bending stress is σ_p=345 MPa. Calculations for gear 1 with 38 teeth: Y = 0.37727 from Table 1. The shaft is rotating at 2650rpm we will do the equations for modules 1.5 and 2.0 to test if any of the gears are usable (in this example only modules of 1.5 and 2.0 are used, to simplify but in reality all modules should be checked): Module m (in mm/tooth) 1.5 2.0 Calculate the pinion pitch diameter from Equation 4: d_p=m×N (mm) 57 mm 76 mm Calculate the pitch line velocity from Equation 3: V=d_p/2×ω (m/s) 7.9 m/s 10.5 m/s Calculate the velocity factor from Equation 5 K_v=6.1/(6.1+V) 0.4357 0.3675 Calculate the transmitted load from Equation 2: W_t=Power/V (N) 2276 N 1707 N Calculate the face width by rearranging Equation 1 F=W_t/(K_v σmY) 0.027 m 0.018 m From our calculations the gear with module 1.5 requires a face width of 27mm which is larger than the 20 mm from the catalogue in Table 4. The gear with module 2.0 requires a face width of 18 mm which is lower than the 25 mm from the catalogue in Table 5. Calculations for pinion 1: Y = 0.29327 from Table 1 and n = 5594 rpm (after adjusting by using the gear ratio). (no need to calculate for m = 1.5 as it has been rejected) Module m (in mm/tooth) 2.0 Calculate the pinion pitch diameter from Equation 4: d_p=m×N (mm) 36 mm Calculate the pitch line velocity from Equation 3: V=d_p/2×ω (m/s) 10.5 m/s Calculate the velocity factor from Equation 5 K_v=6.1/(6.1+V) 0.3676 Calculate the transmitted load from Equation 2: W_t=Power/V (N) 1707 N Calculate the face width by rearranging Equation 1 F=W_t/(K_v σmY) 0.023 m For the second pair of gears, rinse and repeat, do all the steps for all the modules. From my calculations m = 1.5 gives a face width value greater than the catalogue value of 20 mm, so try m = 2 which gives a face width value less than the catalogue value of 25 mm, so design is OK. Let’s run the calculations for the second gear with 38 teeth: Y = 0.37727 from Table 1 and n = 5594 rpm (it’s in contact with Pinion 1) Module m (in mm/tooth) 2.0 Calculate the pinion pitch diameter from Equation 4: d_p=m×N (mm) 76 mm Calculate the pitch line velocity from Equation 3: V=d_p/2×ω (m/s) 22.26 m/s Calculate the velocity factor from Equation 5 K_v=6.1/(6.1+V) 0.215 Calculate the transmitted load from Equation 2: W_t=Power/V (N) 808.6 N Calculate the face width by rearranging Equation 1 F=W_t/(K_v σmY) 0.0144 m Calculations for pinion 2: Y = 0.29327 from Table 1 and n = 11810 rpm (after adjusting by using the gear ratio). Module m (in mm/tooth) 2.0 Calculate the pinion pitch diameter from Equation 4: d_p=m×N (mm) 36 mm Calculate the pitch line velocity from Equation 3: V=d_p/2×ω (m/s) 22.26 m/s Calculate the velocity factor from Equation 5 K_v=6.1/(6.1+V) 0.215 Calculate the transmitted load from Equation 2: W_t=Power/V (N) 808.6 N Calculate the face width by rearranging Equation 1 F=W_t/(K_v σmY) 0.0186 m 18.6 mm is below the catalogue value of 25 mm so design is OK   Challenge: +Solve questions 8, 9, 10, 11, 12, 13, 14 and 15 from the Tutorial on Gears. +Solve the question below: A gearbox is required to transmit xx kW from a shaft rotating at yyyy rpm. The desired output speed is approximately 20 000 rpm. For space limitation and standardisation reasons a double step-up gearbox is requested with equal ratios. Using the limited selection of gears presented in Tables 2 to 5, select suitable gears for the gear wheels and pinions. Take xx as the first two digits from your student id number and the rpm as the last four digits of your student id to solve the question. Each tutorial question is worth 10%. The question in this assignment is worth 20%. Table 3 – Spur Gears: 1.0 module, heavy duty steel 817M40, 655M13, face width 15 mm Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) SG1-9 9 10.00 12.00 12 6 SG1-46 46 46.00 48.00 30 8 SG1-10 10 11.00 13.00 13 6 SG1-47 47 47.00 49.00 30 8 SG1-11 11 12.00 14.00 14 6 SG1-48 48 48.00 50.00 30 8 SG1-12 12 12.00 14.00 14 6 SG1-49 49 49.00 51.00 30 8 SG1-13 13 13.00 15.00 15 6 SG1-50 50 50.00 52.00 35 10 SG1-14 14 14.00 16.00 16 6 SG1-51 51 51.00 53.00 35 10 SG1-15 15 15.00 17.00 17 6 SG1-52 52 52.00 54.00 35 10 SG1-16 16 16.00 18.00 18 8 SG1-53 53 53.00 55.00 35 10 SG1-17 17 17.00 19.00 18 8 SG1-54 54 54.00 56.00 35 10 SG1-18 18 18.00 20.00 18 8 SG1-55 55 55.00 57.00 35 10 SG1-19 19 19.00 21.00 18 8 SG1-56 56 56.00 58.00 35 10 SG1-20 20 20.00 22.00 20 8 SG1-57 57 57.00 59.00 35 10 SG1-21 21 21.00 23.00 20 8 SG1-58 58 58.00 60.00 35 10 SG1-22 22 22.00 24.00 20 8 SG1-59 59 59.00 61.00 35 10 SG1-23 23 23.00 25.00 20 8 SG1-60 60 60.00 62.00 35 10 SG1-24 24 24.00 26.00 20 8 SG1-61 61 61.00 63.00 35 10 SG1-25 25 25.00 27.00 20 8 SG1-62 62 62.00 64.00 35 10 SG1-26 26 26.00 28.00 25 8 SG1-63 63 63.00 65.00 35 10 SG1-27 27 27.00 29.00 25 8 SG1-64 64 64.00 66.00 35 10 SG1-28 28 28.00 30.00 25 8 SG1-65 65 65.00 67.00 35 10 SG1-29 29 29.00 31.00 25 8 SG1-66 66 66.00 68.00 35 10 SG1-30 30 30.00 32.00 25 8 SG1-68 68 68.00 70.00 35 10 SG1-31 31 31.00 33.00 25 8 SG1-70 70 70.00 72.00 35 10 SG1-32 32 32.00 34.00 25 8 SG1-72 72 72.00 74.00 35 10 SG1-33 33 33.00 35.00 25 8 SG1-74 74 74.00 76.00 45 10 SG1-34 34 34.00 36.00 25 8 SG1-76 76 76.00 78.00 45 10 SG1-35 35 35.00 37.00 25 8 SG1-78 78 78.00 80.00 45 10 SG1-36 36 36.00 38.00 30 8 SG1-80 80 80.00 82.00 45 10 SG1-37 37 37.00 39.00 30 8 SG1-84 84 84.00 86.00 45 10 SG1-38 38 38.00 40.00 30 8 SG1-88 88 88.00 90.00 45 10 SG1-39 39 39.00 41.00 30 8 SG1-90 90 90.00 92.00 45 10 SG1-40 40 40.00 42.00 30 8 SG1-96 96 96.00 98.00 45 10 SG1-41 41 41.00 43.00 30 8 SG1-100 100 100.00 102.00 45 10 SG1-42 42 42.00 44.00 30 8 SG1-112 112 112.00 114.00 45 10 SG1-43 43 43.00 45.00 30 8 SG1-120 120 120.00 122.00 45 10 SG1-44 44 44.00 46.00 30 8 SG1-130 130 130.00 132.00 45 10 SG1-45 45 45.00 47.00 30 8 SG1-150 150 150.00 152.00 45 10 Table 4 – Spur Gears: 1.5 module, heavy duty steel 817M40, 655M13, face width 20 mm Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) SG1.5-9 9 15.00 18.00 18 8 SG1.5-47 47 70.50 73.50 50 15 SG1.5-10 10 16.50 19.50 19.5 8 SG1.5-48 48 72.00 75.00 50 15 SG1.5-11 11 18.00 21.00 21 8 SG1.5-49 49 73.50 76.50 50 15 SG1.5-12 12 18.00 21.00 21 8 SG1.5-50 50 75.00 78.00 50 15 SG1.5-13 13 19.50 22.50 20 8 SG1.5-51 51 76.50 79.50 50 15 SG1.5-14 14 21.00 24.00 20 8 SG1.5-52 52 78.00 81.00 50 15 SG1.5-15 15 22.50 25.50 20 8 SG1.5-53 53 79.50 82.50 60 15 SG1.5-16 16 24.00 27.00 25 10 SG1.5-54 54 81.00 84.00 60 15 SG1.5-17 17 25.50 28.50 25 10 SG1.5-55 55 82.50 85.50 60 15 SG1.5-18 18 27.00 30.00 25 10 SG1.5-56 56 84.00 87.00 60 15 SG1.5-19 19 28.50 31.50 25 10 SG1.5-57 57 85.50 88.50 60 15 SG1.5-20 20 30.00 33.00 25 10 SG1.5-58 58 87.00 90.00 60 15 SG1.5-21 21 31.50 34.50 25 10 SG1.5-59 59 88.50 91.50 60 15 SG1.5-22 22 33.00 36.00 30 10 SG1.5-60 60 90.00 93.00 60 15 SG1.5-23 23 34.50 37.50 30 10 SG1.5-62 62 93.00 96.00 60 15 SG1.5-24 24 36.00 39.00 30 10 SG1.5-64 64 96.00 99.00 60 15 SG1.5-25 25 37.50 40.50 30 10 SG1.5-65 65 97.50 100.50 60 15 SG1.5-26 26 39.00 42.00 30 10 SG1.5-66 66 99.00 102.00 60 15 SG1.5-27 27 40.50 43.50 30 10 SG1.5-68 68 102.00 105.00 60 15 SG1.5-28 28 42.00 45.00 30 10 SG1.5-70 70 105.00 108.00 60 15 SG1.5-29 29 43.50 46.50 30 10 SG1.5-71 71 106.50 109.50 60 15 SG1.5-30 30 45.00 48.00 30 10 SG1.5-72 72 108.00 111.00 60 15 SG1.5-31 31 46.50 49.50 30 10 SG1.5-73 73 109.50 112.50 60 15 SG1.5-32 32 48.00 51.00 30 10 SG1.5-74 74 111.00 114.00 60 15 SG1.5-33 33 49.50 52.50 30 10 SG1.5-75 75 112.50 115.50 60 15 SG1.5-34 34 51.00 54.00 30 10 SG1.5-76 76 114.00 117.00 60 15 SG1.5-35 35 52.50 55.50 50 15 SG1.5-78 78 117.00 120.00 75 15 SG1.5-36 36 54.00 57.00 50 15 SG1.5-80 80 120.00 123.00 75 15 SG1.5-37 37 55.50 58.50 50 15 SG1.5-86 86 129.00 132.00 75 15 SG1.5-38 38 57.00 60.00 50 15 SG1.5-90 90 135.00 138.00 75 15 SG1.5-39 39 58.50 61.50 50 15 SG1.5-96 96 144.00 147.00 75 15 SG1.5-40 40 60.00 63.00 50 15 SG1.5-98 98 147.00 150.00 75 15 SG1.5-41 41 61.50 64.50 50 15 SG1-100 100 150.00 153.00 75 15 SG1.5-42 42 63.00 66.00 50 15 SG1-105 105 157.50 160.50 75 15 SG1.5-43 43 64.50 67.50 50 15 SG1-110 110 165.00 168.00 75 15 SG1.5-44 44 66.00 69.00 50 15 SG1-115 115 175.50 178.50 75 15 SG1.5-45 45 67.50 70.50 50 15 SG1-120 120 180.00 183.00 75 15 SG1.5-46 46 69.00 72.00 50 15   Table 5 – Spur Gears: 2.0 module, heavy duty steel 817M40, 655M13, face width 25 mm Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) SG2-9 9 20.00 24.00 24 12 SG2-47 47 94.00 98.00 60 20 SG2-10 10 22.00 26.00 26 12 SG2-48 48 96.00 100.00 60 20 SG2-11 11 24.00 28.00 28 12 SG2-49 49 98.00 102.00 60 20 SG2-12 12 24.00 28.00 28 12 SG2-50 50 100.00 104.00 60 20 SG2-13 13 26.00 30.00 30 12 SG2-51 51 102.00 106.00 60 20 SG2-14 14 28.00 32.00 30 12 SG2-52 52 104.00 108.00 60 20 SG2-15 15 30.00 34.00 30 12 SG2-53 53 106.00 110.00 60 20 SG2-16 16 32.00 36.00 30 12 SG2-54 54 108.00 112.00 60 20 SG2-17 17 34.00 38.00 35 15 SG2-55 55 110.00 114.00 60 20 SG2-18 18 36.00 40.00 35 15 SG2-56 56 112.00 116.00 60 20 SG2-19 19 38.00 42.00 35 15 SG2-57 57 114.00 118.00 60 20 SG2-20 20 40.00 44.00 35 15 SG2-58 58 116.00 120.00 60 20 SG2-21 21 42.00 46.00 35 15 SG2-59 59 118.00 122.00 60 20 SG2-22 22 44.00 48.00 35 15 SG2-60 60 120.00 124.00 60 20 SG2-23 23 46.00 50.00 35 15 SG2-62 62 124.00 128.00 75 20 SG2-24 24 48.00 52.00 35 15 SG2-64 64 128.00 132.00 75 20 SG2-25 25 50.00 54.00 35 15 SG2-65 65 130.00 134.00 75 20 SG2-26 26 52.00 56.00 35 15 SG2-66 66 132.00 136.00 75 20 SG2-27 27 54.00 58.00 50 20 SG2-68 68 136.00 140.00 75 20 SG2-28 28 56.00 60.00 50 20 SG2-70 70 140.00 144.00 75 20 SG2-29 29 58.00 62.00 50 20 SG2-71 71 142.00 146.00 75 20 SG2-30 30 60.00 64.00 50 20 SG2-72 72 144.00 148.00 75 20 SG2-31 31 62.00 66.00 50 20 SG2-73 73 146.00 150.00 75 20 SG2-32 32 64.00 68.00 50 20 SG2-74 74 148.00 152.00 75 20 SG2-33 33 66.00 70.00 50 20 SG2-75 75 150.00 154.00 75 20 SG2-34 34 68.00 72.00 50 20 SG2-76 76 152.00 156.00 75 20 SG2-35 35 70.00 74.00 50 20 SG2-78 78 156.00 160.00 100 20 SG2-36 36 72.00 76.00 50 20 SG2-80 80 160.00 164.00 100 20 SG2-37 37 74.00 78.00 50 20 SG2-86 86 172.00 176.00 100 20 SG2-38 38 76.00 80.00 50 20 SG2-90 90 180.00 184.00 100 20 SG2-39 39 78.00 82.00 50 20 SG2-96 96 192.00 196.00 100 20 SG2-40 40 80.00 84.00 50 20 SG2-98 98 196.00 200.00 100 20 SG2-41 41 82.00 86.00 50 20 SG2-100 100 200.00 204.00 100 20 SG2-42 42 84.00 88.00 50 20 SG2-105 105 210.00 214.00 100 20 SG2-43 43 86.00 90.00 60 20 SG2-110 110 220.00 224.00 100 20 SG2-44 44 88.00 92.00 60 20 SG2-115 115 230.00 234.00 100 20 SG2-45 45 90.00 94.00 60 20 SG2-120 120 240.00 244.00 100 20 SG2-46 46 92.00 96.00 60 20   Table 6 – 6.10 Spur Gears: 3.0 module, heavy duty steel 817M40, 655M13, face width 35 mm Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) SG3-9 9 30.00 36.00 36 15 SG3-45 45 135.00 141.00 100 25 SG3-10 10 33.00 39.00 39 15 SG3-46 46 138.00 144.00 100 25 SG3-11 11 36.00 42.00 42 15 SG3-47 47 141.00 147.00 100 25 SG3-12 12 36.00 42.00 42 20 SG3-48 48 144.00 150.00 100 25 SG3-13 13 39.00 45.00 45 20 SG3-49 49 147.00 153.00 100 25 SG3-14 14 42.00 48.00 45 20 SG3-50 50 150.00 156.00 100 25 SG3-15 15 45.00 51.00 45 20 SG3-51 51 153.00 159.00 100 25 SG3-16 16 48.00 54.00 45 20 SG3-52 52 156.00 162.00 100 25 SG3-17 17 51.00 57.00 45 20 SG3-53 53 159.00 165.00 100 25 SG3-18 18 54.00 60.00 45 20 SG3-54 54 162.00 168.00 100 25 SG3-19 19 57.00 63.00 45 20 SG3-55 55 165.00 171.00 100 25 SG3-20 20 60.00 66.00 60 25 SG3-56 56 168.00 174.00 100 25 SG3-21 21 63.00 69.00 60 25 SG3-57 57 171.00 177.00 127 25 SG3-22 22 66.00 72.00 60 25 SG3-58 58 174.00 180.00 127 25 SG3-23 23 69.00 75.00 60 25 SG3-59 59 177.00 183.00 127 25 SG3-24 24 72.00 78.00 60 25 SG3-60 60 180.00 186.00 127 25 SG3-25 25 75.00 81.00 60 25 SG3-62 62 186.00 192.00 127 25 SG3-26 26 78.00 84.00 60 25 SG3-63 63 189.00 195.00 127 25 SG3-27 27 81.00 87.00 60 25 SG3-64 64 192.00 198.00 127 25 SG3-28 28 84.00 90.00 60 25 SG3-65 65 195.00 201.00 127 25 SG3-29 29 87.00 93.00 60 25 SG3-68 68 204.00 210.00 127 25 SG3-30 30 90.00 96.00 60 25 SG3-70 70 210.00 216.00 150 30 SG3-31 31 93.00 99.00 60 25 SG3-72 72 216.00 222.00 150 30 SG3-32 32 96.00 102.00 60 25 SG3-75 75 225.00 231.00 150 30 SG3-33 33 99.00 105.00 60 25 SG3-76 76 228.00 234.00 150 30 SG3-34 34 102.00 108.00 75 25 SG3-78 78 234.00 240.00 150 30 SG3-35 35 105.00 111.00 75 25 SG3-80 80 240.00 246.00 150 30 SG3-36 36 108.00 114.00 75 25 SG3-82 82 246.00 252.00 150 30 SG3-37 37 111.00 117.00 75 25 SG3-84 84 252.00 258.00 150 30 SG3-38 38 114.00 120.00 75 25 SG3-86 86 258.00 264.00 150 30 SG3-39 39 117.00 123.00 75 25 SG3-90 90 270.00 276.00 150 30 SG3-40 40 120.00 126.00 75 25 SG3-92 92 276.00 282.00 150 30 SG3-41 41 123.00 129.00 75 25 SG3-94 94 282.00 288.00 150 30 SG3-42 42 126.00 132.00 75 25 SG3-95 95 285.00 291.00 150 30 SG3-43 43 129.00 135.00 75 25 SG3-96 96 288.00 294.00 150 30 SG3-44 44 132.00 138.00 100 25 Marking Criteria Max Grade Rationale Each tutorial question is worth 10%. The question in this assignment is worth 20%. Total Mark will be presented on TurnItIn. This document can be scanned and submitted online or in person.

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Faculty of Computing, Engineering and Science

 

 

Assessment Cover Sheet and Feedback Form 2019-20

Module Code:
 

NG3S229

 

Module Title:
 

Mechanics and Control

 

Module Team:
 

Fan Zhang
Joao Ramos

 

Assessment Title
and Tasks:
 

Report 1

 

Assessment No.
 

1

 

Date Set:
 

04-Nov-19

 

Submission Date:
 

06-Dec-19

 

Return Date:
 

13-Jan-20

 

IT IS YOUR RESPONSIBILITY TO KEEP RECORDS OF ALL WORK
SUBMITTED

Marking
and Assessment
 
This assignment will be marked out of 100%
 
This assignment contributes to 15% of the total module marks.
 
Learning Outcomes to be assessed (as specified in the validated module
descriptor https://icis.southwales.ac.uk/ ):
 

1) Demonstrate
an understanding of complex static and dynamics systems and solve problems
using experimental analysis
2) Demonstrate
an understanding and apply the concepts of static and dynamic analysis to
solve complex engineering problems
 
 

Provisional
mark only: subject to change and / or confirmation by the Assessment Board
 
Assessment
Task: GEARS

 
Your task is to solve
the following questions. This is not a Report but an extended Tutorial,
please submit all your workings in a clear
and concise manner
– clearly outlining the result for each question.
                                                           

Required Information: Lewis Formula

The Lewis formula
is a simple approach to calculating the bending stress in gears, given by:

  Equation 1

Where:

 – bending
stress in a gear (N/m2)

 –
transmitted load (N) (found by using Equation 2)

 – velocity
factor (found by using Equation 5)

 – face width
(m)

 – module
(m/tooth)

 – Lewis form
factor Y (found in Table 1)

The Load
transmitted by the Gear

:

  Equation 2

Where:

 –
transmitted load (N)

 – Power
transmitted (W)

 – pitch line
velocity (m/s)

The pitch line velocity

:

  Equation 3

Where:

 – pitch line
velocity (m/s)

 – pinion
pitch diameter (m)

 – angular
velocity (rad/s)

The pinion pitch diameter

:

  Equation 4

Where:

 – module
(m/tooth or mm/tooth)

 – number of
teeth

The velocity factor

, given by the Barth equation:

  Equation 5

Where:

 – velocity
factor

 – pitch line
velocity (m/s)

Table 1 – Values for the Lewis
form factor Y defined for two different tooth standards (Mitchener and Mabie
1982)

N, number of
teeth

Y (φ = 20°; a =
m; b = 1.25 m)

 

12

0.22960

 

13

0.24317

 

14

0.25530

 

15

0.26622

 

16

0.27610

 

17

0.28508

 

18

0.29327

 

19

0.30078

 

20

0.30769

 

21

0.31406

 

22

0.31997

 

24

0.33056

 

26

0.33979

 

28

0.34790

 

30

0.35510

 

34

0.36731

 

38

0.37727

 

45

0.39093

 

50

0.39860

 

60

0.41047

 

75

0.42283

 

100

0.43574

 

150

0.44930

 

300

0.46364

 

Rack

0.47897

 

 

a – addendum

 

b – dedendum

 

φ – pressure angle

 

m – module

Table
2 – Permissible bending stresses for various commonly used gear
materials

Material

Treatment

σUTS (MPa)

Permissible bending stress σp (MPa)

Nylon

 

65 (20°C)

27

Tufnol

110

31

080M40

540

131

080M40

Induction hardened

540

117

817M40

772

221

817M40

Induction hardened

772

183

045M10

494

117

045M10

Case hardened

494

276

655M13

Case hardened

849

345

Example 1: A 20° full depth spur pinion is to transmit 1.25 kW at 850 rpm. The
pinion has 18 teeth. Determine the Lewis bending stress if the module is 2
and the face width is 25 mm
:
Step by step solution:
Calculate the pinion pitch
diameter from
Equation 4:


Calculate the pitch line velocity
from
Equation 3:


Calculate the velocity factor
from
Equation 5:


Calculate the transmitted load
from
Equation 2:

Calculate the bending stress
load from
Equation 1, taking the Lewis form factor Y from Table 1 for 18 teeth Y=0.29327:

Example 2: A gearbox is required to transmit 18 kW from a shaft rotating at 2650
rpm. The desired output speed is approximately 12 000 rpm. For space
limitation and standardisation reasons a double step-up gearbox is requested
with equal ratios. Using the limited selection of gears presented in Tables 2
to 5, select suitable gears for the gear wheels and pinions.
Step by step solution:
The steps are the following:
Sketch the solutionFind the gear ratioSelect a materialSelect a gear from the table by rearranging
the Lewis equation (
Equation 1) to find the gear face width F and.

Finding the gear ratio:


Total gear ratio of 1 to 4.528. A double gearbox is requested with
equal ratios. Therefore the ratio for each gear pair should be:

 
Note that the minimum number of teeth permissible when using a
pressure angle of 20° is 18.

This means the small gear needs to have 18 teeth. So the large gear
should have approximately:


The nearest integer is 38. This gives us a real gear ratio of

 for each gear pair.

Selecting a material:
The next step is to select a material. The stronger steel in Table 2 is the 655M13 which will be selected prior to a more detailed
consideration. For 655M13, the permissible bending stress is

.
Calculations for gear 1 with 38 teeth: Y = 0.37727 from Table 1. The
shaft is rotating at 2650rpm we will do the equations for modules 1.5 and 2.0
to test if any of the gears are usable (in this example only modules of 1.5
and 2.0 are used, to simplify but in reality all modules should be checked):

 

Module
m (in mm/tooth)

1.5

2.0

Calculate the pinion pitch diameter from Equation 4:

57 mm

76 mm

Calculate the pitch line
velocity from Equation 3:

7.9 m/s

10.5 m/s

Calculate the velocity factor
from
Equation 5

0.4357

0.3675

Calculate the transmitted load
from
Equation 2:

2276 N

1707 N

Calculate the face width by
rearranging
Equation 1

0.027 m

0.018 m

 
From our calculations the gear
with module 1.5 requires a face width of 27mm which is larger than the 20 mm
from the catalogue in Table 4. The gear with module 2.0 requires a face width of 18 mm which is
lower than the 25 mm from the catalogue in Table 5.
Calculations for pinion 1: Y = 0.29327 from Table 1 and n = 5594 rpm
(after adjusting by using the gear ratio). (no need to calculate for m = 1.5
as it has been rejected)

 

Module
m (in mm/tooth)

2.0

Calculate the pinion pitch diameter from Equation 4:

36 mm

Calculate the pitch line
velocity from Equation 3:

10.5 m/s

Calculate the velocity factor
from
Equation 5

0.3676

Calculate the transmitted load
from
Equation 2:

1707 N

Calculate the face width by
rearranging
Equation 1

0.023 m

 
For the second pair of gears,
rinse and repeat, do all the steps for all the modules. From my calculations
m = 1.5 gives a face width value greater than the catalogue value of 20 mm,
so try m = 2 which gives a face width value less than the catalogue value of
25 mm, so design is OK.
Let’s run the calculations for
the second gear with 38 teeth: Y = 0.37727
from Table 1 and n = 5594 rpm (it’s in contact with Pinion 1)

 

Module
m (in mm/tooth)

2.0

Calculate the pinion pitch diameter from Equation 4:

76 mm

Calculate the pitch line
velocity from Equation 3:

22.26 m/s

Calculate the velocity factor
from
Equation 5

0.215

Calculate the transmitted load
from
Equation 2:

808.6 N

Calculate the face width by
rearranging
Equation 1

0.0144 m

 
Calculations for pinion 2: Y = 0.29327 from Table 1 and n = 11810 rpm
(after adjusting by using the gear ratio).

 

Module
m (in mm/tooth)

2.0

Calculate the pinion pitch diameter from Equation 4:

36 mm

Calculate the pitch line
velocity from Equation 3:

22.26 m/s

Calculate the velocity factor
from
Equation 5

0.215

Calculate the transmitted load
from
Equation 2:

808.6 N

Calculate the face width by
rearranging
Equation 1

0.0186 m

 
18.6 mm is below the catalogue
value of 25 mm so design is OK
 

Challenge:
+Solve questions 8, 9, 10, 11, 12, 13, 14 and 15 from the Tutorial on
Gears.

+Solve the question below:
A gearbox is required to
transmit xx kW from a shaft rotating at yyyy rpm. The desired output speed is
approximately 20 000 rpm. For space limitation and standardisation reasons a
double step-up gearbox is requested with equal ratios. Using the limited
selection of gears presented in Tables 2 to 5, select suitable gears for the
gear wheels and pinions.
Take xx as the first two
digits from your student id number and the rpm as the last four digits of
your student id to solve the question.
Each
tutorial question is worth 10%. The question in this assignment is worth 20%.

Table 3 – Spur Gears: 1.0 module, heavy duty steel 817M40, 655M13, face
width 15 mm

Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm)
SG1-9 9 10.00 12.00 12 6 SG1-46 46 46.00 48.00 30 8
SG1-10 10 11.00 13.00 13 6 SG1-47 47 47.00 49.00 30 8
SG1-11 11 12.00 14.00 14 6 SG1-48 48 48.00 50.00 30 8
SG1-12 12 12.00 14.00 14 6 SG1-49 49 49.00 51.00 30 8
SG1-13 13 13.00 15.00 15 6 SG1-50 50 50.00 52.00 35 10
SG1-14 14 14.00 16.00 16 6 SG1-51 51 51.00 53.00 35 10
SG1-15 15 15.00 17.00 17 6 SG1-52 52 52.00 54.00 35 10
SG1-16 16 16.00 18.00 18 8 SG1-53 53 53.00 55.00 35 10
SG1-17 17 17.00 19.00 18 8 SG1-54 54 54.00 56.00 35 10
SG1-18 18 18.00 20.00 18 8 SG1-55 55 55.00 57.00 35 10
SG1-19 19 19.00 21.00 18 8 SG1-56 56 56.00 58.00 35 10
SG1-20 20 20.00 22.00 20 8 SG1-57 57 57.00 59.00 35 10
SG1-21 21 21.00 23.00 20 8 SG1-58 58 58.00 60.00 35 10
SG1-22 22 22.00 24.00 20 8 SG1-59 59 59.00 61.00 35 10
SG1-23 23 23.00 25.00 20 8 SG1-60 60 60.00 62.00 35 10
SG1-24 24 24.00 26.00 20 8 SG1-61 61 61.00 63.00 35 10
SG1-25 25 25.00 27.00 20 8 SG1-62 62 62.00 64.00 35 10
SG1-26 26 26.00 28.00 25 8 SG1-63 63 63.00 65.00 35 10
SG1-27 27 27.00 29.00 25 8 SG1-64 64 64.00 66.00 35 10
SG1-28 28 28.00 30.00 25 8 SG1-65 65 65.00 67.00 35 10
SG1-29 29 29.00 31.00 25 8 SG1-66 66 66.00 68.00 35 10
SG1-30 30 30.00 32.00 25 8 SG1-68 68 68.00 70.00 35 10
SG1-31 31 31.00 33.00 25 8 SG1-70 70 70.00 72.00 35 10
SG1-32 32 32.00 34.00 25 8 SG1-72 72 72.00 74.00 35 10
SG1-33 33 33.00 35.00 25 8 SG1-74 74 74.00 76.00 45 10
SG1-34 34 34.00 36.00 25 8 SG1-76 76 76.00 78.00 45 10
SG1-35 35 35.00 37.00 25 8 SG1-78 78 78.00 80.00 45 10
SG1-36 36 36.00 38.00 30 8 SG1-80 80 80.00 82.00 45 10
SG1-37 37 37.00 39.00 30 8 SG1-84 84 84.00 86.00 45 10
SG1-38 38 38.00 40.00 30 8 SG1-88 88 88.00 90.00 45 10
SG1-39 39 39.00 41.00 30 8 SG1-90 90 90.00 92.00 45 10
SG1-40 40 40.00 42.00 30 8 SG1-96 96 96.00 98.00 45 10
SG1-41 41 41.00 43.00 30 8 SG1-100 100 100.00 102.00 45 10
SG1-42 42 42.00 44.00 30 8 SG1-112 112 112.00 114.00 45 10
SG1-43 43 43.00 45.00 30 8 SG1-120 120 120.00 122.00 45 10
SG1-44 44 44.00 46.00 30 8 SG1-130 130 130.00 132.00 45 10
SG1-45 45 45.00 47.00 30 8 SG1-150 150 150.00 152.00 45 10

Table 4 – Spur Gears: 1.5
module, heavy duty steel 817M40, 655M13, face width 20 mm

Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm)
SG1.5-9 9 15.00 18.00 18 8 SG1.5-47 47 70.50 73.50 50 15
SG1.5-10 10 16.50 19.50 19.5 8 SG1.5-48 48 72.00 75.00 50 15
SG1.5-11 11 18.00 21.00 21 8 SG1.5-49 49 73.50 76.50 50 15
SG1.5-12 12 18.00 21.00 21 8 SG1.5-50 50 75.00 78.00 50 15
SG1.5-13 13 19.50 22.50 20 8 SG1.5-51 51 76.50 79.50 50 15
SG1.5-14 14 21.00 24.00 20 8 SG1.5-52 52 78.00 81.00 50 15
SG1.5-15 15 22.50 25.50 20 8 SG1.5-53 53 79.50 82.50 60 15
SG1.5-16 16 24.00 27.00 25 10 SG1.5-54 54 81.00 84.00 60 15
SG1.5-17 17 25.50 28.50 25 10 SG1.5-55 55 82.50 85.50 60 15
SG1.5-18 18 27.00 30.00 25 10 SG1.5-56 56 84.00 87.00 60 15
SG1.5-19 19 28.50 31.50 25 10 SG1.5-57 57 85.50 88.50 60 15
SG1.5-20 20 30.00 33.00 25 10 SG1.5-58 58 87.00 90.00 60 15
SG1.5-21 21 31.50 34.50 25 10 SG1.5-59 59 88.50 91.50 60 15
SG1.5-22 22 33.00 36.00 30 10 SG1.5-60 60 90.00 93.00 60 15
SG1.5-23 23 34.50 37.50 30 10 SG1.5-62 62 93.00 96.00 60 15
SG1.5-24 24 36.00 39.00 30 10 SG1.5-64 64 96.00 99.00 60 15
SG1.5-25 25 37.50 40.50 30 10 SG1.5-65 65 97.50 100.50 60 15
SG1.5-26 26 39.00 42.00 30 10 SG1.5-66 66 99.00 102.00 60 15
SG1.5-27 27 40.50 43.50 30 10 SG1.5-68 68 102.00 105.00 60 15
SG1.5-28 28 42.00 45.00 30 10 SG1.5-70 70 105.00 108.00 60 15
SG1.5-29 29 43.50 46.50 30 10 SG1.5-71 71 106.50 109.50 60 15
SG1.5-30 30 45.00 48.00 30 10 SG1.5-72 72 108.00 111.00 60 15
SG1.5-31 31 46.50 49.50 30 10 SG1.5-73 73 109.50 112.50 60 15
SG1.5-32 32 48.00 51.00 30 10 SG1.5-74 74 111.00 114.00 60 15
SG1.5-33 33 49.50 52.50 30 10 SG1.5-75 75 112.50 115.50 60 15
SG1.5-34 34 51.00 54.00 30 10 SG1.5-76 76 114.00 117.00 60 15
SG1.5-35 35 52.50 55.50 50 15 SG1.5-78 78 117.00 120.00 75 15
SG1.5-36 36 54.00 57.00 50 15 SG1.5-80 80 120.00 123.00 75 15
SG1.5-37 37 55.50 58.50 50 15 SG1.5-86 86 129.00 132.00 75 15
SG1.5-38 38 57.00 60.00 50 15 SG1.5-90 90 135.00 138.00 75 15
SG1.5-39 39 58.50 61.50 50 15 SG1.5-96 96 144.00 147.00 75 15
SG1.5-40 40 60.00 63.00 50 15 SG1.5-98 98 147.00 150.00 75 15
SG1.5-41 41 61.50 64.50 50 15 SG1-100 100 150.00 153.00 75 15
SG1.5-42 42 63.00 66.00 50 15 SG1-105 105 157.50 160.50 75 15
SG1.5-43 43 64.50 67.50 50 15 SG1-110 110 165.00 168.00 75 15
SG1.5-44 44 66.00 69.00 50 15 SG1-115 115 175.50 178.50 75 15
SG1.5-45 45 67.50 70.50 50 15 SG1-120 120 180.00 183.00 75 15
SG1.5-46 46 69.00 72.00 50 15            

Table 5 – Spur Gears: 2.0
module, heavy duty steel 817M40, 655M13, face width 25 mm

Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm)
SG2-9 9 20.00 24.00 24 12 SG2-47 47 94.00 98.00 60 20
SG2-10 10 22.00 26.00 26 12 SG2-48 48 96.00 100.00 60 20
SG2-11 11 24.00 28.00 28 12 SG2-49 49 98.00 102.00 60 20
SG2-12 12 24.00 28.00 28 12 SG2-50 50 100.00 104.00 60 20
SG2-13 13 26.00 30.00 30 12 SG2-51 51 102.00 106.00 60 20
SG2-14 14 28.00 32.00 30 12 SG2-52 52 104.00 108.00 60 20
SG2-15 15 30.00 34.00 30 12 SG2-53 53 106.00 110.00 60 20
SG2-16 16 32.00 36.00 30 12 SG2-54 54 108.00 112.00 60 20
SG2-17 17 34.00 38.00 35 15 SG2-55 55 110.00 114.00 60 20
SG2-18 18 36.00 40.00 35 15 SG2-56 56 112.00 116.00 60 20
SG2-19 19 38.00 42.00 35 15 SG2-57 57 114.00 118.00 60 20
SG2-20 20 40.00 44.00 35 15 SG2-58 58 116.00 120.00 60 20
SG2-21 21 42.00 46.00 35 15 SG2-59 59 118.00 122.00 60 20
SG2-22 22 44.00 48.00 35 15 SG2-60 60 120.00 124.00 60 20
SG2-23 23 46.00 50.00 35 15 SG2-62 62 124.00 128.00 75 20
SG2-24 24 48.00 52.00 35 15 SG2-64 64 128.00 132.00 75 20
SG2-25 25 50.00 54.00 35 15 SG2-65 65 130.00 134.00 75 20
SG2-26 26 52.00 56.00 35 15 SG2-66 66 132.00 136.00 75 20
SG2-27 27 54.00 58.00 50 20 SG2-68 68 136.00 140.00 75 20
SG2-28 28 56.00 60.00 50 20 SG2-70 70 140.00 144.00 75 20
SG2-29 29 58.00 62.00 50 20 SG2-71 71 142.00 146.00 75 20
SG2-30 30 60.00 64.00 50 20 SG2-72 72 144.00 148.00 75 20
SG2-31 31 62.00 66.00 50 20 SG2-73 73 146.00 150.00 75 20
SG2-32 32 64.00 68.00 50 20 SG2-74 74 148.00 152.00 75 20
SG2-33 33 66.00 70.00 50 20 SG2-75 75 150.00 154.00 75 20
SG2-34 34 68.00 72.00 50 20 SG2-76 76 152.00 156.00 75 20
SG2-35 35 70.00 74.00 50 20 SG2-78 78 156.00 160.00 100 20
SG2-36 36 72.00 76.00 50 20 SG2-80 80 160.00 164.00 100 20
SG2-37 37 74.00 78.00 50 20 SG2-86 86 172.00 176.00 100 20
SG2-38 38 76.00 80.00 50 20 SG2-90 90 180.00 184.00 100 20
SG2-39 39 78.00 82.00 50 20 SG2-96 96 192.00 196.00 100 20
SG2-40 40 80.00 84.00 50 20 SG2-98 98 196.00 200.00 100 20
SG2-41 41 82.00 86.00 50 20 SG2-100 100 200.00 204.00 100 20
SG2-42 42 84.00 88.00 50 20 SG2-105 105 210.00 214.00 100 20
SG2-43 43 86.00 90.00 60 20 SG2-110 110 220.00 224.00 100 20
SG2-44 44 88.00 92.00 60 20 SG2-115 115 230.00 234.00 100 20
SG2-45 45 90.00 94.00 60 20 SG2-120 120 240.00 244.00 100 20
SG2-46 46 92.00 96.00 60 20            

Table 6 – 6.10 Spur Gears: 3.0 module, heavy duty steel 817M40, 655M13,
face width 35 mm

Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm)
SG3-9 9 30.00 36.00 36 15 SG3-45 45 135.00 141.00 100 25
SG3-10 10 33.00 39.00 39 15 SG3-46 46 138.00 144.00 100 25
SG3-11 11 36.00 42.00 42 15 SG3-47 47 141.00 147.00 100 25
SG3-12 12 36.00 42.00 42 20 SG3-48 48 144.00 150.00 100 25
SG3-13 13 39.00 45.00 45 20 SG3-49 49 147.00 153.00 100 25
SG3-14 14 42.00 48.00 45 20 SG3-50 50 150.00 156.00 100 25
SG3-15 15 45.00 51.00 45 20 SG3-51 51 153.00 159.00 100 25
SG3-16 16 48.00 54.00 45 20 SG3-52 52 156.00 162.00 100 25
SG3-17 17 51.00 57.00 45 20 SG3-53 53 159.00 165.00 100 25
SG3-18 18 54.00 60.00 45 20 SG3-54 54 162.00 168.00 100 25
SG3-19 19 57.00 63.00 45 20 SG3-55 55 165.00 171.00 100 25
SG3-20 20 60.00 66.00 60 25 SG3-56 56 168.00 174.00 100 25
SG3-21 21 63.00 69.00 60 25 SG3-57 57 171.00 177.00 127 25
SG3-22 22 66.00 72.00 60 25 SG3-58 58 174.00 180.00 127 25
SG3-23 23 69.00 75.00 60 25 SG3-59 59 177.00 183.00 127 25
SG3-24 24 72.00 78.00 60 25 SG3-60 60 180.00 186.00 127 25
SG3-25 25 75.00 81.00 60 25 SG3-62 62 186.00 192.00 127 25
SG3-26 26 78.00 84.00 60 25 SG3-63 63 189.00 195.00 127 25
SG3-27 27 81.00 87.00 60 25 SG3-64 64 192.00 198.00 127 25
SG3-28 28 84.00 90.00 60 25 SG3-65 65 195.00 201.00 127 25
SG3-29 29 87.00 93.00 60 25 SG3-68 68 204.00 210.00 127 25
SG3-30 30 90.00 96.00 60 25 SG3-70 70 210.00 216.00 150 30
SG3-31 31 93.00 99.00 60 25 SG3-72 72 216.00 222.00 150 30
SG3-32 32 96.00 102.00 60 25 SG3-75 75 225.00 231.00 150 30
SG3-33 33 99.00 105.00 60 25 SG3-76 76 228.00 234.00 150 30
SG3-34 34 102.00 108.00 75 25 SG3-78 78 234.00 240.00 150 30
SG3-35 35 105.00 111.00 75 25 SG3-80 80 240.00 246.00 150 30
SG3-36 36 108.00 114.00 75 25 SG3-82 82 246.00 252.00 150 30
SG3-37 37 111.00 117.00 75 25 SG3-84 84 252.00 258.00 150 30
SG3-38 38 114.00 120.00 75 25 SG3-86 86 258.00 264.00 150 30
SG3-39 39 117.00 123.00 75 25 SG3-90 90 270.00 276.00 150 30
SG3-40 40 120.00 126.00 75 25 SG3-92 92 276.00 282.00 150 30
SG3-41 41 123.00 129.00 75 25 SG3-94 94 282.00 288.00 150 30
SG3-42 42 126.00 132.00 75 25 SG3-95 95 285.00 291.00 150 30
SG3-43 43 129.00 135.00 75 25 SG3-96 96 288.00 294.00 150 30
SG3-44 44 132.00 138.00 100 25            
Marking Criteria Max Grade Rationale
Each
tutorial question is worth 10%. The question in this assignment is worth 20%.

Total
Mark will be presented on TurnItIn. This document can be scanned and submitted
online or in person.

The post Faculty of Computing, Engineering and Science Assessment Cover Sheet and Feedback Form 2019-20 Module Code: NG3S229 Module Title: Mechanics and Control Module Team: Fan Zhang Joao Ramos Assessment Title and Tasks: Report 1 Assessment No. 1 Date Set: 04-Nov-19 Submission Date: 06-Dec-19 Return Date: 13-Jan-20 IT IS YOUR RESPONSIBILITY TO KEEP RECORDS OF ALL WORK SUBMITTED Marking and Assessment This assignment will be marked out of 100% This assignment contributes to 15% of the total module marks. Learning Outcomes to be assessed (as specified in the validated module descriptor https://icis.southwales.ac.uk/ ): 1) Demonstrate an understanding of complex static and dynamics systems and solve problems using experimental analysis 2) Demonstrate an understanding and apply the concepts of static and dynamic analysis to solve complex engineering problems Provisional mark only: subject to change and / or confirmation by the Assessment Board   Assessment Task: GEARS Your task is to solve the following questions. This is not a Report but an extended Tutorial, please submit all your workings in a clear and concise manner – clearly outlining the result for each question. Required Information: Lewis Formula The Lewis formula is a simple approach to calculating the bending stress in gears, given by: σ=W_t/(K_v FmY) (N/m^2) Equation 1 Where: σ – bending stress in a gear (N/m2) W_t – transmitted load (N) (found by using Equation 2) K_v – velocity factor (found by using Equation 5) F – face width (m) m – module (m/tooth) Y – Lewis form factor Y (found in Table 1) The Load transmitted by the Gear W_t: W_t=Power/V (N) Equation 2 Where: W_t – transmitted load (N) Power – Power transmitted (W) V – pitch line velocity (m/s) The pitch line velocity V: V=d_p/2×ω (m/s) Equation 3 Where: V – pitch line velocity (m/s) d_p – pinion pitch diameter (m) ω – angular velocity (rad/s) The pinion pitch diameter d_p: d_p=m×N (m or mm) Equation 4 Where: m – module (m/tooth or mm/tooth) N – number of teeth The velocity factor K_v, given by the Barth equation: K_v=6.1/(6.1+V) (N/m^2) Equation 5 Where: K_v – velocity factor V – pitch line velocity (m/s)   Table 1 – Values for the Lewis form factor Y defined for two different tooth standards (Mitchener and Mabie 1982) N, number of teeth Y (φ = 20°; a = m; b = 1.25 m) 12 0.22960 13 0.24317 14 0.25530 15 0.26622 16 0.27610 17 0.28508 18 0.29327 19 0.30078 20 0.30769 21 0.31406 22 0.31997 24 0.33056 26 0.33979 28 0.34790 30 0.35510 34 0.36731 38 0.37727 45 0.39093 50 0.39860 60 0.41047 75 0.42283 100 0.43574 150 0.44930 300 0.46364 Rack 0.47897 a – addendum b – dedendum φ – pressure angle m – module Table 2 – Permissible bending stresses for various commonly used gear materials Material Treatment σUTS (MPa) Permissible bending stress σp (MPa) Nylon 65 (20°C) 27 Tufnol 110 31 080M40 540 131 080M40 Induction hardened 540 117 817M40 772 221 817M40 Induction hardened 772 183 045M10 494 117 045M10 Case hardened 494 276 655M13 Case hardened 849 345 Example 1: A 20° full depth spur pinion is to transmit 1.25 kW at 850 rpm. The pinion has 18 teeth. Determine the Lewis bending stress if the module is 2 and the face width is 25 mm: Step by step solution: Calculate the pinion pitch diameter from Equation 4: d_p=m×N=2 mm/tooth×18 teeth=36 mm=0.036 m Calculate the pitch line velocity from Equation 3: V=d_p/2×ω =0.036/2×850×2π/60=1.602 m/s Calculate the velocity factor from Equation 5: K_v=6.1/(6.1+V)=6.1/(6.1+1.602)=0.792 (N/m^2) Calculate the transmitted load from Equation 2: W_t=Power/V=1250/1.602=780.2 (N) Calculate the bending stress load from Equation 1, taking the Lewis form factor Y from Table 1 for 18 teeth Y=0.29327: σ=W_t/(K_v FmY)=780.2/(0.792×0.025×0.002×0.29327)=67.18 (MN/m^2) Example 2: A gearbox is required to transmit 18 kW from a shaft rotating at 2650 rpm. The desired output speed is approximately 12 000 rpm. For space limitation and standardisation reasons a double step-up gearbox is requested with equal ratios. Using the limited selection of gears presented in Tables 2 to 5, select suitable gears for the gear wheels and pinions. Step by step solution: The steps are the following: Sketch the solution Find the gear ratio Select a material Select a gear from the table by rearranging the Lewis equation (Equation 1) to find the gear face width F and. Finding the gear ratio: G=(12 000 rpm)/(2650 rpm)=4.528 Total gear ratio of 1 to 4.528. A double gearbox is requested with equal ratios. Therefore the ratio for each gear pair should be: √G=√4.528=2.128 Note that the minimum number of teeth permissible when using a pressure angle of 20° is 18. This means the small gear needs to have 18 teeth. So the large gear should have approximately: 18×G=18×2.128=38.3 The nearest integer is 38. This gives us a real gear ratio of 38/18=2.11 for each gear pair. Selecting a material: The next step is to select a material. The stronger steel in Table 2 is the 655M13 which will be selected prior to a more detailed consideration. For 655M13, the permissible bending stress is σ_p=345 MPa. Calculations for gear 1 with 38 teeth: Y = 0.37727 from Table 1. The shaft is rotating at 2650rpm we will do the equations for modules 1.5 and 2.0 to test if any of the gears are usable (in this example only modules of 1.5 and 2.0 are used, to simplify but in reality all modules should be checked): Module m (in mm/tooth) 1.5 2.0 Calculate the pinion pitch diameter from Equation 4: d_p=m×N (mm) 57 mm 76 mm Calculate the pitch line velocity from Equation 3: V=d_p/2×ω (m/s) 7.9 m/s 10.5 m/s Calculate the velocity factor from Equation 5 K_v=6.1/(6.1+V) 0.4357 0.3675 Calculate the transmitted load from Equation 2: W_t=Power/V (N) 2276 N 1707 N Calculate the face width by rearranging Equation 1 F=W_t/(K_v σmY) 0.027 m 0.018 m From our calculations the gear with module 1.5 requires a face width of 27mm which is larger than the 20 mm from the catalogue in Table 4. The gear with module 2.0 requires a face width of 18 mm which is lower than the 25 mm from the catalogue in Table 5. Calculations for pinion 1: Y = 0.29327 from Table 1 and n = 5594 rpm (after adjusting by using the gear ratio). (no need to calculate for m = 1.5 as it has been rejected) Module m (in mm/tooth) 2.0 Calculate the pinion pitch diameter from Equation 4: d_p=m×N (mm) 36 mm Calculate the pitch line velocity from Equation 3: V=d_p/2×ω (m/s) 10.5 m/s Calculate the velocity factor from Equation 5 K_v=6.1/(6.1+V) 0.3676 Calculate the transmitted load from Equation 2: W_t=Power/V (N) 1707 N Calculate the face width by rearranging Equation 1 F=W_t/(K_v σmY) 0.023 m For the second pair of gears, rinse and repeat, do all the steps for all the modules. From my calculations m = 1.5 gives a face width value greater than the catalogue value of 20 mm, so try m = 2 which gives a face width value less than the catalogue value of 25 mm, so design is OK. Let’s run the calculations for the second gear with 38 teeth: Y = 0.37727 from Table 1 and n = 5594 rpm (it’s in contact with Pinion 1) Module m (in mm/tooth) 2.0 Calculate the pinion pitch diameter from Equation 4: d_p=m×N (mm) 76 mm Calculate the pitch line velocity from Equation 3: V=d_p/2×ω (m/s) 22.26 m/s Calculate the velocity factor from Equation 5 K_v=6.1/(6.1+V) 0.215 Calculate the transmitted load from Equation 2: W_t=Power/V (N) 808.6 N Calculate the face width by rearranging Equation 1 F=W_t/(K_v σmY) 0.0144 m Calculations for pinion 2: Y = 0.29327 from Table 1 and n = 11810 rpm (after adjusting by using the gear ratio). Module m (in mm/tooth) 2.0 Calculate the pinion pitch diameter from Equation 4: d_p=m×N (mm) 36 mm Calculate the pitch line velocity from Equation 3: V=d_p/2×ω (m/s) 22.26 m/s Calculate the velocity factor from Equation 5 K_v=6.1/(6.1+V) 0.215 Calculate the transmitted load from Equation 2: W_t=Power/V (N) 808.6 N Calculate the face width by rearranging Equation 1 F=W_t/(K_v σmY) 0.0186 m 18.6 mm is below the catalogue value of 25 mm so design is OK   Challenge: +Solve questions 8, 9, 10, 11, 12, 13, 14 and 15 from the Tutorial on Gears. +Solve the question below: A gearbox is required to transmit xx kW from a shaft rotating at yyyy rpm. The desired output speed is approximately 20 000 rpm. For space limitation and standardisation reasons a double step-up gearbox is requested with equal ratios. Using the limited selection of gears presented in Tables 2 to 5, select suitable gears for the gear wheels and pinions. Take xx as the first two digits from your student id number and the rpm as the last four digits of your student id to solve the question. Each tutorial question is worth 10%. The question in this assignment is worth 20%. Table 3 – Spur Gears: 1.0 module, heavy duty steel 817M40, 655M13, face width 15 mm Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) SG1-9 9 10.00 12.00 12 6 SG1-46 46 46.00 48.00 30 8 SG1-10 10 11.00 13.00 13 6 SG1-47 47 47.00 49.00 30 8 SG1-11 11 12.00 14.00 14 6 SG1-48 48 48.00 50.00 30 8 SG1-12 12 12.00 14.00 14 6 SG1-49 49 49.00 51.00 30 8 SG1-13 13 13.00 15.00 15 6 SG1-50 50 50.00 52.00 35 10 SG1-14 14 14.00 16.00 16 6 SG1-51 51 51.00 53.00 35 10 SG1-15 15 15.00 17.00 17 6 SG1-52 52 52.00 54.00 35 10 SG1-16 16 16.00 18.00 18 8 SG1-53 53 53.00 55.00 35 10 SG1-17 17 17.00 19.00 18 8 SG1-54 54 54.00 56.00 35 10 SG1-18 18 18.00 20.00 18 8 SG1-55 55 55.00 57.00 35 10 SG1-19 19 19.00 21.00 18 8 SG1-56 56 56.00 58.00 35 10 SG1-20 20 20.00 22.00 20 8 SG1-57 57 57.00 59.00 35 10 SG1-21 21 21.00 23.00 20 8 SG1-58 58 58.00 60.00 35 10 SG1-22 22 22.00 24.00 20 8 SG1-59 59 59.00 61.00 35 10 SG1-23 23 23.00 25.00 20 8 SG1-60 60 60.00 62.00 35 10 SG1-24 24 24.00 26.00 20 8 SG1-61 61 61.00 63.00 35 10 SG1-25 25 25.00 27.00 20 8 SG1-62 62 62.00 64.00 35 10 SG1-26 26 26.00 28.00 25 8 SG1-63 63 63.00 65.00 35 10 SG1-27 27 27.00 29.00 25 8 SG1-64 64 64.00 66.00 35 10 SG1-28 28 28.00 30.00 25 8 SG1-65 65 65.00 67.00 35 10 SG1-29 29 29.00 31.00 25 8 SG1-66 66 66.00 68.00 35 10 SG1-30 30 30.00 32.00 25 8 SG1-68 68 68.00 70.00 35 10 SG1-31 31 31.00 33.00 25 8 SG1-70 70 70.00 72.00 35 10 SG1-32 32 32.00 34.00 25 8 SG1-72 72 72.00 74.00 35 10 SG1-33 33 33.00 35.00 25 8 SG1-74 74 74.00 76.00 45 10 SG1-34 34 34.00 36.00 25 8 SG1-76 76 76.00 78.00 45 10 SG1-35 35 35.00 37.00 25 8 SG1-78 78 78.00 80.00 45 10 SG1-36 36 36.00 38.00 30 8 SG1-80 80 80.00 82.00 45 10 SG1-37 37 37.00 39.00 30 8 SG1-84 84 84.00 86.00 45 10 SG1-38 38 38.00 40.00 30 8 SG1-88 88 88.00 90.00 45 10 SG1-39 39 39.00 41.00 30 8 SG1-90 90 90.00 92.00 45 10 SG1-40 40 40.00 42.00 30 8 SG1-96 96 96.00 98.00 45 10 SG1-41 41 41.00 43.00 30 8 SG1-100 100 100.00 102.00 45 10 SG1-42 42 42.00 44.00 30 8 SG1-112 112 112.00 114.00 45 10 SG1-43 43 43.00 45.00 30 8 SG1-120 120 120.00 122.00 45 10 SG1-44 44 44.00 46.00 30 8 SG1-130 130 130.00 132.00 45 10 SG1-45 45 45.00 47.00 30 8 SG1-150 150 150.00 152.00 45 10 Table 4 – Spur Gears: 1.5 module, heavy duty steel 817M40, 655M13, face width 20 mm Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) SG1.5-9 9 15.00 18.00 18 8 SG1.5-47 47 70.50 73.50 50 15 SG1.5-10 10 16.50 19.50 19.5 8 SG1.5-48 48 72.00 75.00 50 15 SG1.5-11 11 18.00 21.00 21 8 SG1.5-49 49 73.50 76.50 50 15 SG1.5-12 12 18.00 21.00 21 8 SG1.5-50 50 75.00 78.00 50 15 SG1.5-13 13 19.50 22.50 20 8 SG1.5-51 51 76.50 79.50 50 15 SG1.5-14 14 21.00 24.00 20 8 SG1.5-52 52 78.00 81.00 50 15 SG1.5-15 15 22.50 25.50 20 8 SG1.5-53 53 79.50 82.50 60 15 SG1.5-16 16 24.00 27.00 25 10 SG1.5-54 54 81.00 84.00 60 15 SG1.5-17 17 25.50 28.50 25 10 SG1.5-55 55 82.50 85.50 60 15 SG1.5-18 18 27.00 30.00 25 10 SG1.5-56 56 84.00 87.00 60 15 SG1.5-19 19 28.50 31.50 25 10 SG1.5-57 57 85.50 88.50 60 15 SG1.5-20 20 30.00 33.00 25 10 SG1.5-58 58 87.00 90.00 60 15 SG1.5-21 21 31.50 34.50 25 10 SG1.5-59 59 88.50 91.50 60 15 SG1.5-22 22 33.00 36.00 30 10 SG1.5-60 60 90.00 93.00 60 15 SG1.5-23 23 34.50 37.50 30 10 SG1.5-62 62 93.00 96.00 60 15 SG1.5-24 24 36.00 39.00 30 10 SG1.5-64 64 96.00 99.00 60 15 SG1.5-25 25 37.50 40.50 30 10 SG1.5-65 65 97.50 100.50 60 15 SG1.5-26 26 39.00 42.00 30 10 SG1.5-66 66 99.00 102.00 60 15 SG1.5-27 27 40.50 43.50 30 10 SG1.5-68 68 102.00 105.00 60 15 SG1.5-28 28 42.00 45.00 30 10 SG1.5-70 70 105.00 108.00 60 15 SG1.5-29 29 43.50 46.50 30 10 SG1.5-71 71 106.50 109.50 60 15 SG1.5-30 30 45.00 48.00 30 10 SG1.5-72 72 108.00 111.00 60 15 SG1.5-31 31 46.50 49.50 30 10 SG1.5-73 73 109.50 112.50 60 15 SG1.5-32 32 48.00 51.00 30 10 SG1.5-74 74 111.00 114.00 60 15 SG1.5-33 33 49.50 52.50 30 10 SG1.5-75 75 112.50 115.50 60 15 SG1.5-34 34 51.00 54.00 30 10 SG1.5-76 76 114.00 117.00 60 15 SG1.5-35 35 52.50 55.50 50 15 SG1.5-78 78 117.00 120.00 75 15 SG1.5-36 36 54.00 57.00 50 15 SG1.5-80 80 120.00 123.00 75 15 SG1.5-37 37 55.50 58.50 50 15 SG1.5-86 86 129.00 132.00 75 15 SG1.5-38 38 57.00 60.00 50 15 SG1.5-90 90 135.00 138.00 75 15 SG1.5-39 39 58.50 61.50 50 15 SG1.5-96 96 144.00 147.00 75 15 SG1.5-40 40 60.00 63.00 50 15 SG1.5-98 98 147.00 150.00 75 15 SG1.5-41 41 61.50 64.50 50 15 SG1-100 100 150.00 153.00 75 15 SG1.5-42 42 63.00 66.00 50 15 SG1-105 105 157.50 160.50 75 15 SG1.5-43 43 64.50 67.50 50 15 SG1-110 110 165.00 168.00 75 15 SG1.5-44 44 66.00 69.00 50 15 SG1-115 115 175.50 178.50 75 15 SG1.5-45 45 67.50 70.50 50 15 SG1-120 120 180.00 183.00 75 15 SG1.5-46 46 69.00 72.00 50 15   Table 5 – Spur Gears: 2.0 module, heavy duty steel 817M40, 655M13, face width 25 mm Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) SG2-9 9 20.00 24.00 24 12 SG2-47 47 94.00 98.00 60 20 SG2-10 10 22.00 26.00 26 12 SG2-48 48 96.00 100.00 60 20 SG2-11 11 24.00 28.00 28 12 SG2-49 49 98.00 102.00 60 20 SG2-12 12 24.00 28.00 28 12 SG2-50 50 100.00 104.00 60 20 SG2-13 13 26.00 30.00 30 12 SG2-51 51 102.00 106.00 60 20 SG2-14 14 28.00 32.00 30 12 SG2-52 52 104.00 108.00 60 20 SG2-15 15 30.00 34.00 30 12 SG2-53 53 106.00 110.00 60 20 SG2-16 16 32.00 36.00 30 12 SG2-54 54 108.00 112.00 60 20 SG2-17 17 34.00 38.00 35 15 SG2-55 55 110.00 114.00 60 20 SG2-18 18 36.00 40.00 35 15 SG2-56 56 112.00 116.00 60 20 SG2-19 19 38.00 42.00 35 15 SG2-57 57 114.00 118.00 60 20 SG2-20 20 40.00 44.00 35 15 SG2-58 58 116.00 120.00 60 20 SG2-21 21 42.00 46.00 35 15 SG2-59 59 118.00 122.00 60 20 SG2-22 22 44.00 48.00 35 15 SG2-60 60 120.00 124.00 60 20 SG2-23 23 46.00 50.00 35 15 SG2-62 62 124.00 128.00 75 20 SG2-24 24 48.00 52.00 35 15 SG2-64 64 128.00 132.00 75 20 SG2-25 25 50.00 54.00 35 15 SG2-65 65 130.00 134.00 75 20 SG2-26 26 52.00 56.00 35 15 SG2-66 66 132.00 136.00 75 20 SG2-27 27 54.00 58.00 50 20 SG2-68 68 136.00 140.00 75 20 SG2-28 28 56.00 60.00 50 20 SG2-70 70 140.00 144.00 75 20 SG2-29 29 58.00 62.00 50 20 SG2-71 71 142.00 146.00 75 20 SG2-30 30 60.00 64.00 50 20 SG2-72 72 144.00 148.00 75 20 SG2-31 31 62.00 66.00 50 20 SG2-73 73 146.00 150.00 75 20 SG2-32 32 64.00 68.00 50 20 SG2-74 74 148.00 152.00 75 20 SG2-33 33 66.00 70.00 50 20 SG2-75 75 150.00 154.00 75 20 SG2-34 34 68.00 72.00 50 20 SG2-76 76 152.00 156.00 75 20 SG2-35 35 70.00 74.00 50 20 SG2-78 78 156.00 160.00 100 20 SG2-36 36 72.00 76.00 50 20 SG2-80 80 160.00 164.00 100 20 SG2-37 37 74.00 78.00 50 20 SG2-86 86 172.00 176.00 100 20 SG2-38 38 76.00 80.00 50 20 SG2-90 90 180.00 184.00 100 20 SG2-39 39 78.00 82.00 50 20 SG2-96 96 192.00 196.00 100 20 SG2-40 40 80.00 84.00 50 20 SG2-98 98 196.00 200.00 100 20 SG2-41 41 82.00 86.00 50 20 SG2-100 100 200.00 204.00 100 20 SG2-42 42 84.00 88.00 50 20 SG2-105 105 210.00 214.00 100 20 SG2-43 43 86.00 90.00 60 20 SG2-110 110 220.00 224.00 100 20 SG2-44 44 88.00 92.00 60 20 SG2-115 115 230.00 234.00 100 20 SG2-45 45 90.00 94.00 60 20 SG2-120 120 240.00 244.00 100 20 SG2-46 46 92.00 96.00 60 20   Table 6 – 6.10 Spur Gears: 3.0 module, heavy duty steel 817M40, 655M13, face width 35 mm Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) Part number Teeth PCD (mm) Outer diam. (mm) Boss diam. (mm) Bore diam. (mm) SG3-9 9 30.00 36.00 36 15 SG3-45 45 135.00 141.00 100 25 SG3-10 10 33.00 39.00 39 15 SG3-46 46 138.00 144.00 100 25 SG3-11 11 36.00 42.00 42 15 SG3-47 47 141.00 147.00 100 25 SG3-12 12 36.00 42.00 42 20 SG3-48 48 144.00 150.00 100 25 SG3-13 13 39.00 45.00 45 20 SG3-49 49 147.00 153.00 100 25 SG3-14 14 42.00 48.00 45 20 SG3-50 50 150.00 156.00 100 25 SG3-15 15 45.00 51.00 45 20 SG3-51 51 153.00 159.00 100 25 SG3-16 16 48.00 54.00 45 20 SG3-52 52 156.00 162.00 100 25 SG3-17 17 51.00 57.00 45 20 SG3-53 53 159.00 165.00 100 25 SG3-18 18 54.00 60.00 45 20 SG3-54 54 162.00 168.00 100 25 SG3-19 19 57.00 63.00 45 20 SG3-55 55 165.00 171.00 100 25 SG3-20 20 60.00 66.00 60 25 SG3-56 56 168.00 174.00 100 25 SG3-21 21 63.00 69.00 60 25 SG3-57 57 171.00 177.00 127 25 SG3-22 22 66.00 72.00 60 25 SG3-58 58 174.00 180.00 127 25 SG3-23 23 69.00 75.00 60 25 SG3-59 59 177.00 183.00 127 25 SG3-24 24 72.00 78.00 60 25 SG3-60 60 180.00 186.00 127 25 SG3-25 25 75.00 81.00 60 25 SG3-62 62 186.00 192.00 127 25 SG3-26 26 78.00 84.00 60 25 SG3-63 63 189.00 195.00 127 25 SG3-27 27 81.00 87.00 60 25 SG3-64 64 192.00 198.00 127 25 SG3-28 28 84.00 90.00 60 25 SG3-65 65 195.00 201.00 127 25 SG3-29 29 87.00 93.00 60 25 SG3-68 68 204.00 210.00 127 25 SG3-30 30 90.00 96.00 60 25 SG3-70 70 210.00 216.00 150 30 SG3-31 31 93.00 99.00 60 25 SG3-72 72 216.00 222.00 150 30 SG3-32 32 96.00 102.00 60 25 SG3-75 75 225.00 231.00 150 30 SG3-33 33 99.00 105.00 60 25 SG3-76 76 228.00 234.00 150 30 SG3-34 34 102.00 108.00 75 25 SG3-78 78 234.00 240.00 150 30 SG3-35 35 105.00 111.00 75 25 SG3-80 80 240.00 246.00 150 30 SG3-36 36 108.00 114.00 75 25 SG3-82 82 246.00 252.00 150 30 SG3-37 37 111.00 117.00 75 25 SG3-84 84 252.00 258.00 150 30 SG3-38 38 114.00 120.00 75 25 SG3-86 86 258.00 264.00 150 30 SG3-39 39 117.00 123.00 75 25 SG3-90 90 270.00 276.00 150 30 SG3-40 40 120.00 126.00 75 25 SG3-92 92 276.00 282.00 150 30 SG3-41 41 123.00 129.00 75 25 SG3-94 94 282.00 288.00 150 30 SG3-42 42 126.00 132.00 75 25 SG3-95 95 285.00 291.00 150 30 SG3-43 43 129.00 135.00 75 25 SG3-96 96 288.00 294.00 150 30 SG3-44 44 132.00 138.00 100 25 Marking Criteria Max Grade Rationale Each tutorial question is worth 10%. The question in this assignment is worth 20%. Total Mark will be presented on TurnItIn. This document can be scanned and submitted online or in person. appeared first on Essay Fix.

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